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Vinay T Johnleft a comment
@Andrew This is a very interesting concept & all the very best.
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Vinay T Johnleft a comment
Hey Brian, The tool is cool. I felt the gradient value useful but can't get my head around the exponent value. In majority of the cases the exponent value should be directly correlated to the exponent value. Congratulation & all the best to Josh & you.
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